学进去-教育应平等而普惠
试题
类型:阅读选择
难度系数:0.40
所属科目:小学英语

A young officer was at a railway station. On his way home, he wanted to telephone his mother to tell her the time of his train, so that she could meet him at the station in her car. He looked in all his pockets, but found that he did not have the right money for the telephone, so he went outside and looked around for someone to help him.

At last an old soldier came by, and the young officer stopped him and said, “Have you got change for ten pence?”

“Wait a moment,” the old soldier answered, beginning to put his hand in his pocket, “I’ll see whether I can help you.”

“Don’t you know how to speak to an officer?” the young man said angrily. “Now let’s start again. Have you got change for ten pence? “No, sir.” The old soldier answered quickly.

1.The young officer wanted to telephone his mother to tell her ______. (     )
A.that he was going to visit herB.when his train would leave
C.when his train would arriveD.that he was now at the railway station
2.He looked around for help because he ______. (     )
A.didn’t have coins for the phone callB.had no money to make the phone call
C.didn’t have the local moneyD.wanted to change money
3.The old soldier ______ at last. (     )
A.was glad to help himB.didn’t know if he had coins
C.didn’t want to help himD.was angry
4.The young officer was angry because he thought the old soldier ______. (     )
A.didn’t know how to speak to himB.didn’t want to help him
C.didn’t answer him correctlyD.was not friendly to him
5.The old soldier in the story was ______. (     )
A.cleverB.stupidC.politeD.friendly
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y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19
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