方法一:先摆3捆小棒表示30,从3捆小棒拿走2捆,还剩1捆,1捆就是10根.
方法二:利用数的组成.
30是3个十,20是2个十,从3个十里面减掉2个十是( )个十,是10,所以30-20=( ).
方法三:用相加算减法.
因为20+( )=30,所以30-20=( ).
方法四:相同数位相减.
因为3-2=( ),所以30-20=( ).
同类型试题
y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2
y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2