学进去-教育应平等而普惠
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类型:七选五
难度系数:0.40
所属科目:高中英语

The Pomodoro Technique was developed by Francesco Cirillo in the 1980s. The technique uses a timer to divide your work into 25-minute sessions called "pomodori."1.When you have completed four pomodori, it's time for a longer break of 20 to 30 minutes. It's simple and easy to use. Follow the steps below to start using it.

●Check your schedule. Your first step is to check your schedule. 2.Estimate how long each task should take you, in terms of the number of pomodori you will need to complete it.

●Set your timer. Before you start, make sure that you have everything you need. Set your timer for the work period you've settled on.

●Take a short break. When your timer goes off, take a five-minute break.You should do this even if you're busy, because these breaks are your time to rest and "recharge your batteries."3.The Pomodoro approach works by maintaining your energy, so that you don't need to work on tasks when your concentration levels are low.

4.When your break is over, reset your timer for the next session and continue your work. When you've completed four pomodori, take a 20- to 30-minute break. Use it to go for a walk, have lunch, read a book... anything, so long as it takes you away from your desk for a while and clears your mind.

Remember, it is important to listen to your body. If your mind starts to wander or you start to feel tired, don't push through to the end of the session.5.It may be that three pomodori followed by a 20-minute break suits you best, or that five sessions followed by a 30-minute break is better.

A.You might want to experiment with this.
B.You can use whatever sort of timer you like.
C.After each session, you take a five-minute break.
D.Irregular short breaks help to keep you focused and energetic.
E.Continue your work sessions and take a longer break.
F.Cirillo argues that energy levels are far more important than time.
G.Look at your to-do list and think about what you need to do today.
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y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19
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