学进去-教育应平等而普惠
试题
类型:填空题
难度系数:0.15
所属科目:高中信息技术
(加试题)维吉尼亚密码。如下图所示,分别用行和列表示待加密的字符(明文)和当前字符的密钥,行和列的交叉点的字符即为加密后的结果(密文)。在加密时,密文与明文的字母大小写形式保持一致,如:明文字母为大写,则加密后的密文字母也为大写;当密钥长度不足时重复使用密钥。

 

例如:当明文M=HelloWorld,密钥K=abc时,密文C=HfnlpYosnd。运算过程如下所示:
明文:HelloWorld
密钥:abcabcabca
密文:HfnlpYosnd
依据上述算法描述设计了如下VB程序。请回答下列问题:
(1)若明文是Jia,密钥是Pass,则输出的密文是:_________
(2)请在划线处填上合适的代码
Const MIN_ASC = 65
Function X2D(x As String) As String
Dim s As String, zf As String, i As Integer
s = ""
For i = 1 To Len(x)
zf = Mid(x, i, 1)
If zf >= "a" And zf <= "z" Then
s=s+ ________
Else
s = s + zf
End If
Next i
X2D = s
End Function
Private Sub Command1_Click()
Dim M As String, K As String, C As String, flag As Boolean
Dim i As Integer, t As Integer, ch As Integer, pos As Integer, j As Integer
M = Text1.Text       '明文
K = Text2.Text       '密钥
t = Len(K)
K = X2D(K)          
C = ""
For i = 1 To Len(M)
ch = Asc(Mid(M, i, 1))
flag = False
If ch >= 97 And ch <= 122 Then ch = ch - 32: flag = True
pos= ________                 '密钥的字符位置值
If pos = 0 Then pos = t
j = Asc(Mid(K, pos, 1))      '密钥字符的ASCII值
ch = ch - MIN_ASC
j = j - MIN_ASC
ch= ________
ch = ch + MIN_ASC
If flag Then ch = ch + 32     '设置字母的大小写形式
C = C & Chr(ch)
Next i
Text3.Text = C
End Sub
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y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
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用户名称
2019-09-19

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19
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