

(1)求抛物线的解析式;
(2)问:当t为何值时,△APQ为直角三角形;
(3)过点P作PE∥y轴,交AB于点E,过点Q作QF∥y轴,交抛物线于点F,连接EF,当EF∥PQ时,求点F的坐标;
(4)设抛物线顶点为M,连接BP,BM,MQ,问:是否存在t的值,使以B,Q,M为顶点的三角形与以O,B,P为顶点的三角形相似?若存在,请求出t的值;若不存在,请说明理由.

同类型试题

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2


y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

